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2f^2-6f-6=2
We move all terms to the left:
2f^2-6f-6-(2)=0
We add all the numbers together, and all the variables
2f^2-6f-8=0
a = 2; b = -6; c = -8;
Δ = b2-4ac
Δ = -62-4·2·(-8)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-10}{2*2}=\frac{-4}{4} =-1 $$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+10}{2*2}=\frac{16}{4} =4 $
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